|x^2-10| > 9x помогите решить.

Решите задачу:

$|a|\ \textgreater \ b\; \; \; \Rightarrow \; \; \; \left [ {{a\ \textgreater \ b} \atop {a\ \textless \ -b}} \right. \\\\\\|x^2-10|\ \textgreater \ 9x\; \; \; \to \; \; \; \left [ {{x^2-10\ \textgreater \ 9x} \atop {x^2-10\ \textless \ -9x}} \right. \; ,\; \left [ {{x^2-9x-10\ \textgreater \ 0} \atop {x^2+9x-10\ \textless \ 0}} \right. \; ,\\\\ \left [ {{(x+1)(x-10)\ \textgreater \ 0} \atop {(x-1)(x+10)\ \textless \ 0}} \right. \; ,\; \left [ {{x\in (-\infty ,-1)\cup (10,+\infty )} \atop {x\in (-10,1)}} \right. \; \Rightarrow \; \; x\in (-\infty ,1)U(10,+\infty )$