1) sin 2x = √3/2 2) cos 3x = - 1/2 3) tg 2x = 1

Question

1) sin 2x = √3/2
2) cos 3x = - 1/2
3) tg 2x = 1

Answer 1

1. 2x=(-1^n)п/3+пn
x=(-1^n)п/6 + пn/2
2. 3x=+- 2п/3+ 2пn
x=+- 2п/6+ 2пn/3
3. 2x=п/4+пn
x=п/8+ пn/2