Cos*(2p-3x)*cosx+sin3x*cos(3p/2+x) найдите х
Решение cos(2π - 3x)cosx + sin3xcos(3π/2 + x) = 0 cos3xcosx + sin3xsinx = 0 cos(3x - x) = 0 cos2x = 0 2x = π/2 + πk, k∈Z x = π/4 + πk/2, k∈Z