Сократите дробь а и в

Решите задачу:

$\frac{3 x^{2} -9x-x+3}{ x^{2} -3x} = \frac{3x(x-3)-(x-3)}{ x(x-3)}= \frac{(3x-1)(x-3)}{ x(x-3)}= \frac{3x-1}{ x}=3- \frac{1}{x}$

$\frac{5 x^{2} +x-4}{ x^{2} +x} = \frac{5 x^{2} +5x-4x-4}{ x^{2} +x} =\frac{5 x(x+1)-4(x+1)}{ x(x+1)} =\frac{(5x-4)(x+1)}{ x(x+1)} = \frac{5x-4}{x} =5- \frac{4}{x}$

$\frac{2 x^{2} -9x+4}{ x^{2} -16} =\frac{2 x^{2} -8x-x+4}{ x^{2} -16} = \frac{2x(x-4)-(x-4)}{ (x-4)(x+4)}= \frac{(x-4)(2x-1)}{ (x-4)(x+4)}= \frac{2x-1}{ x+4}$

$\frac{2 x^{2}+5x-3}{ x^{2} -9} =\frac{2 x^{2}+6x-x-3}{ x^{2} -9} = \frac{2x(x+3)-(x+3)}{ (x-3)(x+3)}= \frac{(x+3)(2x-1)}{ (x-3)(x+3)}= \frac{2x-1}{ x-3}$