(x+1)(x+2)-(x+3)(x+4)=0

Question

(x+1)(x+2)-(x+3)(x+4)=0

Answer 1

X² + 2x + x + 2 - ( x² + 4x + 3x + 12) = 0
x² + 3x + 2 - x² - 7x - 12 = 0
- 4x - 10 = 0
- 4x = 10
4x =- 10
x = - 10/4
x = - 2,5

Answer 2

Х²+2х+х+2 - (х²+4х+3х+12)=0
х²+3х+2-х²-7х-12=0
-4х=-10
х=2,5