Найдите координаты точек пересечения прямой y-x-3=0 с окружностью x2+y2=9
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y-x-3=0
у = х+3
х²+(х+3)²=9
х²+х²+6х+9-9=0
2х²+6х=0
2х(х+3)=0
2х=0 или х+3 = 0
х = 0 х=-3
Если х=0, то у=0+3=3
Если х=-3, то у=-3+3=0
