(x^2+2x-3)/(x^2+3x-10):(x^2+7x+12)/(x^2-9x+14)

Question

(x^2+2x-3)/(x^2+3x-10):(x^2+7x+12)/(x^2-9x+14)

Answer 1

(x^2+2*x-3)/(x^2+3*x-10)/(x^2+7*x+12)/(x^2-9*x+14) = 0

(x-1)/ (x-7)*(x-2)^2*(x+4)*(x+5)=0

x-1=0

x=1

 

ОТвет:1

Answer 2

(x^2+2x-3)/(x^2+3x-10):(x^2+7x+12)/(x^2-9x+14) x^2+2x-3 =(х+3)(х-1)