3x^2+40x+10 <-x^2+11x+3

Question

3x^2+40x+10 <-x^2+11x+3</p>

Answer 1

3x^2+40x+10 <-x^2+11x+3</span>

3x^2+40x+10+x^2-11x-3<0</span>

4x^2+29х+7<0</span>

4x^2+29х+7=0

д=29 в квадрате-4*4*7=841-112=729

х1,2=-29±27/8

х1=-7

х2=-1/4