Решите неравенства, пожалуйста!!!!))

1)
$16^{0.25x^2-1} \leq 16^0 0.25 x^{2} -1 \leq 0$

$x^{2} \leq \frac{1}{0.25}$

$-2 \leq x \leq 2$

2)

$(0,027)^{x-3}\ \textgreater \ \frac{10}{3}$

$0.3^{3x-9}\ \textgreater \ 0.3^{-1}$

$3x-9\ \textless \ -1$

$x\ \textless \ 2\frac{2}{3}$

3)

$4^x+( \frac{1}{2}) ^{-1-x}-8 \geq 0$

$2^{2x}+ 2^{x+1}- 8 \geq 0 2^{x}=t t \geq 0 t^2+2t-8 \geq 0 D=36 t= -4; t=2$

т.к. t>0 то рассмотрим только один промежуток:
$2^{x} \geq 2 x \geq 1$

4)

$3^{2x+2}- 3^{x+4}\ \textless \ 3^{x}-9$

$3^{2x}*9- 3^{x}*81- 3^{x}+9\ \textless \ 0$

$9* 3^{2x}-82* 3^{x}+9\ \textless \ 0 3^x=t; t\ \textgreater \ 0$

$9t^2-82t+9\ \textless \ 0 D=6400 t=9; t= 1/9$

$\frac{1}{9}\ \textless \ 3^x\ \textless \ 9$

$3^{-2}\ \textless \ 3^x\ \textless \ 3^2$

$-2\ \textless \ x\ \textless \ 2$