Помогите решить!
(sin5x - sin3x) / (2cos4x) = sinx
sin5x - sin3x = 2 sin(5x-3x)/2 * cos(5x+3x)/2=2 sin4x cos4x
2 sin4x cos4x/ (2cos4x) = sinx
sin4x = sinx
Ответ
x=πn, n ϵ Z
x=2πn -π/5 , n ϵ Z
x=2πn +π/5 , n ϵ Z
x=2πn -3π/5 , n ϵ Z
x=2πn +3π/5 , n ϵ Z
x=2πn -2π/3 , n ϵ Z
x=2πn +2π/3 , n ϵ Z