Упростите: 1)sin 2β/sin²β= 2)sin 2α/2sin α - cos α= 3)0,5 tg α sin 2α+cos² α= дробью...

Question

Упростите:

1)sin 2β/sin²β=

2)sin 2α/2sin α - cos α=

3)0,5 tg α sin 2α+cos² α=

дробью писать 1 и 2!

Answer 1

1)sin2B/sin^2b=2cosB/sinB=2ctgB

2)sin2a/2sina-cosa=2sinacosa/2sina-cosa=0

3)0,5tga2sinacosa+cos^2a=0,5sina/cosa2sina+cos^2a=sin^a+cos^2a=1

 

Answer 2

1)sin2B/sin^2b=2cosB/sinB=2ctgB

2)sin2a/2sina-cosa=2sinacosa/2sina-cosa=0

3)0,5tga2sinacosa+cos^2a=0,5sina/cosa2sina+cos^2a=sin^a+cos^ 2a=1