Log 4-x (x+3)-log 4-x(x-4)^2>=-2

$log_{4-x}(x+3)-log_{4-x}(x-4)^2 \geq -2\\ log_{4-x}\frac{x+3}{(x-4)^2} \geq -2\\ \left[\begin{array}{ccc}4-x\ \textgreater \ 1\\\frac{x+3}{(x-4)^2}\ \textgreater \ 0\\(x-4)^2 \neq 0\\\frac{x+3}{(x-4)^2} \geq (4-x)^{-2}\end{array}\right\\ \\ \frac{x+3}{(x-4)^2} \geq (4-x)^{-2}\\ \frac{x+3}{(4-x)^2} \geq (4-x)^{-2}\\ x+3\geq(4-x)^{-2}*(4-x)^2\\ x+3 \geq (4-x)^{-2+2}\\ x+3 \geq (4-x)^0\\ x+3 \geq 1\\ x \geq -2\\ \left[\begin{array}{ccc}x\ \textless \ 3\\\x\ \textgreater \ -3\\x \neq 4\\x \geq -2\end{array}\right\\$
смотри рисунок
Овет: [-2; 3)