Помогите с номером 25! Во вложении!

Question

Помогите с номером 25! Во вложении!

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Answer 1

а) arcsin(-1/2) = -π/6 <</strong>  π/6 =arccos√3/2 .
б) arctq√3 =π/3 > π/4 =arctq1 .
в) arccos(1/2) =π/3 > -π/4 =arctq(-1).
г) arctq√3/3 =π/6 <</strong>  π/4 =arctq1.

Answer 2

A) arcSin(-1/2) = -π/6
     arcCos√3/2 = π/3
<<br>б) arctg√3 = π/3
     arctg1 = π/4
>
в)arcCos1/2 = π/3
    arctg(-1) = -π/4
>
г) arcCtg√3/3= π/6
    arctg1 = π/4
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Comments

arcCos√3/2 = π/6