(x+1)^2=(2-x)^2 помогите

Question

(x+1)^2=(2-x)^2 помогите

Answer 1

(x+1)² - (2-x)² =0
(x+1-(2-x))(x+1+2-x)=0
(x+1-2+x)*3 =0
3(2x-1)=0
2x-1=0
2x=1
x=0.5

Answer 2

(X+1)^2 = (2-x)^2 x^2 + 2x + 1 = 4 - 4x + x^2 x^2 - x^2 + 2x + 4x +1 - 4 = 0 6x - 3 = 0 6x = 3 X = 2