6. (6-y)/(1-y²) -(y+3)/(y -y²) =(y+5)/(y+y²) ;
(y -6)/(y² - 1) +(y+3)/(y² -y) =(y+5)/(y+y²) ;
(y -6)/(y - 1)(y + 1) +(y+3)/y(y -1) =(y+5)/y(y+1) ; * * * y ≠±1 , 0. * * *
y(y -6) +(y+3)(y+1) =(y+5)(y-1) ;
y² - 6y + y² + 4y +3 = y² +4y -5 ;
y² -6y +8 =0 ;
y₁=2 ;y₂=4 .
ответ : { 2 ;4 }.