1) sin(α -π) +tq(α -π) + cos(3π/2+α) = - sin(π - α) -tq(π - α) +cos(3π/2+α)=
- sinα +tqα +sinα= tqα.
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2) cos(3π/2+α)*tq(π/2 -α) -sin(3π/2 -α) -ctq(π/2 -α) =
sinα*ctqα +cosα -tqα = cosα+cosα -tqα =2cosα -tqα.
--- вдруг если ---
cos(3π/2+α)*tq(π/2 -α) + sin(3π/2 -α) -ctq(π/2 -α) =
sinα*ctqα -cosα -tqα = cosα-cosα -tqα = -tqα.
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3) ?? (1- ctq²(α -3π/2))/cos(α+π/2) * tq(α -π/2)/(1-ctq²(α -2π)) =
(1- ctq²(3π/2 -α))/cos(π/2 +α) * ( -tq(π/2 -α))/(1-ctq²(2π-α)) =
(1- tq²α)/(-sinα)* (-ctqα)/(1-ctq²α) =(1-tq²α)/(1-ctq²α) *ctqα/sinα=
-tq²α*ctqα/sinα = -tqα/sinα = -1/cosα.