4sin225-6cos120+tg300+3ctg240

Question

4sin225-6cos120+tg300+3ctg240

Answer 1

4sin(180-+45)-6cos(180-60)+tg(360-60)=3ctg(180+60)=

-4*sqrt(2)/2+6*1/2- sqrt(3)+3/ sqrt(3) =-2 sqrt(2)+3- sqrt(3)+ sqrt(3)=3- sqrt(2)