Lg(x-1)+lg(x+1)= 3lg2+lg(x-2)

Question

Lg(x-1)+lg(x+1)= 3lg2+lg(x-2)

Answer 1

Lg(x-1)+lg(x+1)=3lg2+lg(x-2)   ОДЗ: х>1  x>-1  x>2  ⇒  x∈(2;+∞)
lg(x²-1)=lg(8*(x-2))
x²-1=8x-16
x²-8x+15=0  D=4
x₁=5   x₂=3.

Answer 2

Lg(x-1)+lg(x+1)=3lg2+lg(x-2)x:-1x:2=)2