Решите уравнения: 1)x (2x-3)(x-6)=0 2)9x^2-1=0 3)x^3-16x=0
1) x (2x - 3) (x - 6) = 0 x = 0 ; 2x - 3 = 0 ==> x = 3/2 = 1,5 x - 6 = 0 ==> x = 6 2) 9x^2 - 1 = 0 9x^2 = 1 x^2 = 1/9 x = ± √1/9 x = ± 1/3 3) x^3 - 16x = 0 x (x^2 - 16) = 0 x = 0 ; x^2 = 16 x = ± √16 x = ± 4