4/(х-4) - (1-3х)/(2-х) = 8/(x^2-6х+8)

Question

4/(х-4) - (1-3х)/(2-х) = 8/(x^2-6х+8)

Answer 1

4/(x-4)+(1-3x)(x-2)=8/(x-4)(x-2)
x≠4:x≠2
4(x-2)+(1-3x)(x-4)=8
4x-8+x-4-3x²+12x-8=0
3x²-17x+20=0
D=289-240=49
x1=(17-7)/6=5/3
x2=(17+7)/6=4 не удов усл