X³+y³= x+4y+x²-16y²= a³+27-3a-a²= x³+4x²+4x+16= 3x²-48xy+192y²= x²-6x+5=

Question

X³+y³=
x+4y+x²-16y²=
a³+27-3a-a²=
x³+4x²+4x+16=
3x²-48xy+192y²=
x²-6x+5=

Answer 1

X³+y³ = (x+y)(x²-xy+y²)x+4y+x²-16y² = (x+4y)(x-4y+1)
a³+27-3a-a² = (a+3)(a²-4a+9)
x³+4x²+4x+16 = (x+4)(x²+4)
3x²-48xy+192y² = 3(x-8y)²
x²-6x+5 = (x-1)(x-5)