Найти f'(x) y=(1/2x-5)^20

Question

Найти f'(x)
y=(1/2x-5)^20

Answer 1

Y' = 20(1/2x-5)^19*(1/2x-5)'= -20(1/2x-5)*2/(2х-5)²= -40(1/2х-5)^19/(2x-5)²