1) cos60°+tg45° 2)√2 sin45°-√3 tg30° 3)

Question

1) cos60°+tg45°
2)√2 sin45°-√3 tg30°
3)

Answer 1

1) = √3/2+1=(√3+2)/2≈1,866
2) = √2×√2/2-√3×√3/3 = 1-1 = 0
3) =(√3/2)×(√3/2)-1/1 = 3/4-1 = -1/4= -0,25