1)
sinα =3/5 ; α <90°.<br>cosβ =cos(180° -α) = -cosα = -√(1-sin²α) = -√(1 -(3/5)²) = -√(1 -9/25) =
- √(16/25) = -4/5. || α <90°⇒cosα =√(1-sin²α). ||<br>---
2)
tqα*tqβ =tqα*tq(90° -α) = tqα*ctqα =1.
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3)
а) cos(α +β) =1/4 ⇒cosγ = cos(180° -(α +β)) = -cos(α +β) = -1/4.
б) cosγ = -1/4 < 0 ⇒ угол γ тупой .
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4)
tqα =a ⇒ctqβ =ctq(90° -α) =tqα =a.
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5)
cosα =3/5⇒
cosβ =cos(90°-α)=sinα =√(1-cos²α) =√(1-(3/5)²) =√(1-9/25)=√(16/25)=4/5.