Докажите тождество: 2x^2(4x^2-3)(3+4x^2)=32x^6-18x^2

Question

Докажите тождество:
2x^2(4x^2-3)(3+4x^2)=32x^6-18x^2

Answer 1

 x4–10x3+16x+5=0, x4–x3–7x2–8x–6=0