Напишите подробное доказательство!!! Очень нужно!!!!
(tgα+ctgα)*(1-cos(4α)= =(sinα/cosα+cosα/sinα)*(sin²(2α)+cos²(2α)-cos²(2α)+sin²(2α))= =((sin²α+cos²α)/(sinα*cosα))*2*sin²(2α)= =(1/(sinα*cosα))*2*sin²(2α)=(2/(2*sinα*cosα))*2*sin²(2α)= =4*sin²(2α)/sin(2α)≡4*sin(2α).