Решите пожалуйста))!!!
Решение 14^x + 7 = 2^x + 7^(x + 1) (2^x)*(7^x) + 7 - (2^x) - (7^x)*7 = 0 (7^x)*(2^x - 7) - (2^x - 7) = 0 (2^x - 7)*(7^x - 1) = 0 1) 2^x - 7 = 0 3^x = 7 log₃ (3^x) = log₃ 7 x₁ = log₃ 7 2) 7^x - 1 = 0 7^x = 1 7^x = 7⁰ x₂ = 0