(u-4)(4+1)+(4^2-4+1)(4+1) преобразуйте в многочлен.
(u+1)(u-4+u^2-u+1)=\\ (u+1)(u^2-3)=\\ u^3+u^2-3u-3" alt="(u-4)(u+1)+(u^2-u+1)(u+1)=\\ (u+1)(u-4+u^2-u+1)=\\ (u+1)(u^2-3)=\\ u^3+u^2-3u-3" align="absmiddle" class="latex-formula">
(u-4)(4+1)+(4^2-4+1)(4+1) = (4+1)(4^2-4+1+u-4)=5(9+u)=45+5u