У кого есть силы помогите

Решите задачу:

$A2. \ \frac{2b}{b - 1} + \frac{b + 3}{1 - b} = \frac{2b}{b - 1} - \frac{b + 3}{b - 1} = \frac{b - 3}{b - 1} = 0\\\\ b - 1 \ne 0, \ b \ne 1; \ b - 3 = 0, \ \boxed{b = 3}\\\\ A3. \ \frac{8}{2x + 1} = \frac{5}{3x - 2} \ | \ * \ (2x + 1)(3x - 2)\\\\ 2x + 1 \ne 0, \ 2x \ne -1, \ x \ne -\frac{1}{2}; \ 3x - 2 \ne 0, \ 3x \ne 2, \ x \ne \frac{2}{3}\\\\ 8(3x - 2) = 5(2x + 1), \ 24x - 16 = 10x + 5, \ 14x = 21\\\\ x = \frac{21}{14} = \frac{3*7}{2*7} = \boxed{\frac{3}{2}}$