ОДЗ
(2x-1)/(x+2)≥0
x=1/2 x=-2
x∈(-∞;-2) U [1/2;∞)
√(2x-1)/(x+2)=a
a-1/a≥7/12
12a²-7a-12≥0
D=49+576=625
a1=(7-25)/24=-3/4
a2=(7+25)/24=4/3
a<-3/4⇒√(2x-1)/(x+2)<-3/4 нет решения<br>f>4/3⇒√(2x-1)/(x+2)>4/3
(2x-1)/(x+2)>16/9
18x-9>16x+32
18x-16x>32+9
2x>41
x>20,5
x∈(20,5;∞)