Integra 3dx/2x-5 from x=0 to 16

Question

Integra 3dx/2x-5 from x=0 to 16

Comments

Integra dx/6sin^2 6x from x=0 to P/2

Answer 1

=3*(1/2)∫ d(2x-5) /(2x-5)=3/2* ln|2x-5| (от0 до 16)=3/2*(ln|2*16-5| -ln|2*0-
-5|=1,5*(ln17-ln5)=1,5ln(17/5)=1,5*ln3,4

Comments

а 2 пж

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Integra dx/6sin^2 6x from x=0 to P/2

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1/6*1/6*(-ctg (6x))|(от 0 дор/2)=-1/36*(ctgp/2-ctg0)=-1/36*(0-? с пределами интегрирования всё правльно написано?

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да