X( x + 1)(x+ 5)( x+ 6) = 50
x(x^2 + 6x + 5)(x + 6) = 50
x(x^3 + 6x^2 + 6x^2 + 36x + 5x + 30) = 50
x( x^3 + 12x^2 + 41x + 30)= 50
x^4 + 12x^3 + 41x^2 + 30x - 50 = 0
( x^2 + 6x - 5)(x^2 + 6x + 10) = 0
x^2 + 6x - 5 = 0
D = b^2 - 4ac = 36 + 20 = 56
x1 = ( - 6 + √56) / 2
x2 = ( - 6 - √56) /2
x^2 + 6x + 10 = 0
D = b^2 - 4ac = 36 - 40 = - 4 - дискриминант отрицательный,значит,корней нет.