Решите уравнение: 2 x 4
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3x^2+4x+1 x+1 3x+1
2/(3x^2+4x+1)+x/(x+1) = 4/(3x+1) | * (3x^2+4x+1) = (x+1)(3x+1)
2 + x(3x+1) = 4(x+1)
2 + 3x^2 + x = 4x + 4
3x^2 -3x -2 = 0
D = 9 + 24 = 33
x_1 = (3 - V33)/6
x_2 = (3 + V33)/6