10sin(7pi/6)cos(-5pi/4)tg(-3pi/4)

Question

10sin(7pi/6)cos(-5pi/4)tg(-3pi/4)

Answer 1

10sin(π+π/6)*cos(π+π/4)*(-tg(π-π/4))=10*(-sinπ/6)*(-cosπ/4)*tgπ/4)=
=10*(-1/2)*(-√2/2)*1=2,5√2