Log1/3[(2-3x)/x] >=-1
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ОДЗ:
(2-3x)/x >0
__-____(0)_____+____(2/3)_____-
x e (0; 2/3)
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log1/3(2-3x) - log1/3(x) >=-1
log1/3(2-3x) >= log1/3(x)-1
log1/3(2-3x) >= log1/3(x) - log1/3(1/3)
log1/3(2-3x) >= log1/3 ( x/ 1/3)
log1/3(2-3x) >= log1/3(3x)
2-3x<= 3x<br>-3x-3x<=-2<br>-6x<=-2<br>6x>=2
x>=1/3
С учетом ОДЗ: x e [1/3; 2/3)