Решите cos(0,5П-2х)+sinx=0

Question

Решите
cos(0,5П-2х)+sinx=0

Answer 1

Sin2x+sinx=0
2sin(3x/2)cos(x/2)=0
sin(3x/2)=0⇒3x/2=πn⇒x=2πn/3,n∈z
cos(x/2)/2=0⇒x/2=π/2+πk⇒x=π+2πk,k∈z