Упростить выражение 5/6×(2,4х+6/35у)-1,2×(/3х-5/7у)

$\frac{5}{6}(2,4x+\frac{6}{35}y)-1,2(\frac{2}{3}x-\frac{5}{7}y)$ = $\frac{5}{6}*2,4x+\frac{6}{35}y*\frac{5}{6}-1,2(\frac{2}{3}x-\frac{5}{7}y)$ = $5*0,4x+\frac{5}{35}y-1,2(\frac{2}{3}x-\frac{5}{7}y)$ = $2x+\frac{1}{7}y-1,2(\frac{2}{3}x-\frac{5}{7}y)$ = $2x+\frac{1}{7}y-1,2*\frac{2}{3}x-\frac{5}{7}y*(-1,2)$ = $2x+\frac{1}{7}y-0,4*2x+\frac{5}{7}y*1,2$ = $2x+\frac{1}{7}y-0,8x+\frac{6}{7}y$ = $2x-0,8x+\frac{1}{7}y+\frac{6}{7}y$ = $1,2x+\frac{7}{7}y$ = $1,2x+1y$ = $1,2x+y.$