решить систему уравнений {6x+3=8x-3(2y-4) 2(2y-3y)-4x=2y-8

Question

решить систему уравнений {6x+3=8x-3(2y-4) 2(2y-3y)-4x=2y-8

Answer 1

6X + 3 = 8X - 6Y + 12

2X - 6Y + 8 = 0

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- 2Y - 4X - 2Y + 8 = 0

- 4Y - 4X + 8 = 0

-X - Y - 2 = 0

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2X - 6Y + 8 = 0

- X - Y - 2 = 0

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X - 7Y + 6 = 0

X = 7Y - 7

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-2Y -4*(7Y - 7) - 2Y + 8 = 0

- 4Y - 28Y + 28 + 8 = 0

- 32Y = - 36

Y = 1.125

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X = 7Y - 7 = 7.875 - 7 = 0.875