Упростить выражение: (cos2α-cos6α+cos10α-cos14α)/(sin2α+sin6α+sin10α+sin14α)

Question

Упростить выражение:

(cos2α-cos6α+cos10α-cos14α)/(sin2α+sin6α+sin10α+sin14α)

Answer 1

=(2sin4asin2a+2sin12asin2a)/(2sin4acos2a+2sin12acos2a)
=sin2a/cos2a
=tan2a

Answer 2

(cos1a-cos3a+cos5a-cos7a)/(sin1a+sin3a+sin5a+sin7a)