log [2] (3-x)-log [1/2] (1-x)=3
ОДЗ: 3-x>0 =>x<3,<br>1-x>0 => x<1.<br>________________
log [2] (3-x)-log [2] (1/(1-x))=3
log [2] ((3-x)/(1/(1-x))) = 3
log [2] ((3-x)(1-x)) = log [2] (8)
(3-x)(1-x)=8
x²-4x+3-8=0
x²-4x-5=0
x1=-1, (т.к. 1 + (-5) = -4)
x2=-5 / (-1) = 5 - не удовлетворяет ОДЗ.
Ответ: -1.