Решите уравнение: 16cos^{4}x -24cos^{2} x+9=0[tex]
16cosˇ4 x -24cosˇ2 x +9=0 cosˇ2 x=z 16zˇ2 -24z+9=0 (4z)ˇ2 -2.4z.3 +3ˇ2=0 (4z-3)ˇ2 =0 4z-3=0, 4z=3, z=3/4 cosˇ2 x=3/4 1)cosx=√3/2 x=π/6+2k.π x=11π/6+2k.π 2)cosx=-√3/2 x=5π/6+2k.π x=7π/6+2k.π k∈Z