Log1/2(cosП/6+sinП/6) + log1/2(cosП/6-sinП/6)

Question

Log1/2(cosП/6+sinП/6) + log1/2(cosП/6-sinП/6)

Answer 1

Log1/2((cosп/6+sinп/6)(cosп/6-sinп/6)=Log1/2(cos^2п/6-sin^2п/6)=Log1/2(cos2п/6)=log1/2(cosп/3)=log1/2 (1/2)=1 Ответ:1