Пусть a=b/2, c=b-a, d=3b найдите abcd

Question

Пусть a=b/2, c=b-a, d=3b найдите abcd

Answer 1

A=b/2 => b=2a
c=b-a=2a-a=a
d=3b=3*2a=6a
Тогда abcd=a*2a*a*6a=12a^4

Answer 2

A = b/ 2
b = 2a
c = b - a = 2a - a = a
d = 3b = 3•2a = 6a
abcd = a•2a•a•6a = 12a^4