Решение:
1.3х-5=0.25⁻³,
3х-5=(1/4)⁻³,3х-5=4³,3х-5=64,3х=69,х=69:3,х=23
2.2х-1=2³,2х-1=8,2х=8+1,2х=9,х=9:2,х=4.5
3.2πх/7=π/4+πn,n∈Z, 2πx=7π/4+7πn,n∈Z,x= (7π/4)/2π+7πn/2π,
x=7/8+3.5n,n∈Z
4.2x+1=2⁴,2x+1=16, 2x=16-1,2x=15,x=15/2, x=7.5
5.∫(x²(3+4x)²dx=∫x²(9+24x+16x²)dx=∫(9x²+24x³+16x⁴)dx=3x³+6x⁴+16x⁵/5+C
6.cos(x/4+π/6)=-1
Пусть x/4+π/6=t, тогда cost=-1,t=πn,n∈Z
x/4+π/6=πn,n∈Z x/4=πn-π/6,
x=4πn+2π/3, n∈Z-ответ