Log_3 (3-5x) + log_3 2 =log_3 16

Question

Log_3 (3-5x) + log_3 2 =log_3 16

Answer 1

Решение
Log_3 (3-5x) + log_3 2 =log_3 16
ОДЗ: 3 - 5x > 0
5x < 3, x > 0,6
Log_3 (3-5x) =  log_3 16 log_3 2 
Log_3 (3-5x) =  log_3 (16/2)
3 - 5x = 8
5x = 3 - 8
5x = - 5
x = - 1