Разложите ** множители: 1)b²-16 2)25a²-81y² 3)x²-6x+9 4)4y³-y

Question

Разложите на множители:
1)b²-16
2)25a²-81y²
3)x²-6x+9
4)4y³-y

Answer 1

1. b²-16 = (b - 4)*(b+4)
2. 25a²-81y² =  (5a - 9y)*(5a+ 9y)
3. x²-6x+9 = (x - 3)²
4. 4y³-y = y ( 4y² - 1) = y(2y - 1)*(2y+1)

Answer 2

1)b2-16=(b-4)(b+4)
2)25a2-81y2=(5a-9y)(5a+9y)
3)x2-6x+9=(x-3)(x-3)=(x-3)2
4)4y3-y=y(4y2-1)=y(2y-1)(2y+1)