(1/2)-(9/25) решите, пожалуйста)

Решите задачу:

$\frac{1}{2}- \frac{9}{25}= \frac{1}{2}* 1- \frac{9}{25}*1= \frac{1}{2}* \frac{25}{25} - \frac{9}{25}* \frac{2}{2}= \frac{1*25}{2*25}- \frac{9*2}{25*2}=$
$=\frac{1*25-9*2}{25*2}= \frac{25-18}{50}= \frac{7}{50}= \frac{7*1}{5*10}= \frac{7}{5}* \frac{1}{10}= \frac{7*2}{5*2}* \frac{1}{10}= \frac{14}{10}* \frac{1}{10}=$
$=1.4*0.1=0.14$