Решите уравнения 1) (3x-4)2+4x=9x2-24 2) (2x-3)2-x(4x+5)-8=o
(3х-4)²+4х=9х²-24 9х²-24х+16+4х-9х²+24=0 -20х+40=0 -20х=-40 х=2 (2х-3)²-х(4х+5)-8=0 4х²-12х+9-4х²-5х-8=0 -17х+1=0 -17х=-1 х=1/17
(3x-4)²+4x= 9x² -24 (3x)²-2*3x*4+4² +4x = 9x²-24 9x²- 24x +16+4x -9x²+24=0 -20x +40=0 -20x=-40 x= -40/(-20) x= 2 (2x-3)²-x(4x+5) -8=0 4x²-12x+9 -4x²-5x-8=0 -17x +1=0 -17x=-1 17x=1 x= 1/17