Помогите решить интегралы. 46 (Ж,И,Е)

Решите задачу:

$\displaystyle \int\frac{z^3-8}{2-z} \, dz=\int\frac{(z-2)(z^2+2z+4)}{2-z} \, dz = -\int(z^2+2z+4) \, dz = \\ -\left( \frac{z^3}{3} +z^2+4z\right)+C \\ \\ \int\left(\sqrt x+1\right)\left(\sqrt x-1\right) \, dx =\int(x-1) \, dx= \frac{x^2}{2}-x+C$

$\displaystyle \int\frac{x^3+2x+\sqrt x}{x\sqrt x} \, dx= \int\frac{x^3}{x\sqrt x} \, dx+\int\frac{2x}{x\sqrt x} \, dx+\int\frac{\sqrt x}{x\sqrt x} \, dx= \\ \\ \int\frac{x^2}{\sqrt x} \, dx+\int\frac{2}{\sqrt x} \, dx+\int\frac{1}{x} \, dx= \\ \\ \int x^{3/2} \, dx+2\int x^{-1/2} \, dx+\ln|x|= \frac{x^{5/2}}{5/2}+2 \frac{x^{1/2}}{1/2}+\ln|x|+C= \\ \frac{2}{5}x^{5/2}+4x^{1/2}+\ln|x|+C$