1)(-11к)*(2к²-3к+3)= 2)(9ав³-13а²в)*3а²=

Question

1)(-11к)*(2к²-3к+3)=
2)(9ав³-13а²в)*3а²=

Answer 1

1)(-11к)*(2к²-3к+3)=-22к^2+33k^2-33k;2)(9ав³-13а²в)*3а²=27a³b³-39a^4b